What are the solutions to the equation x^2+2^2=4^2 ?

The solutions to the equation x^2+2^2=4^2 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of x^2+2^2=4^2

The zeros of x^2+2^2=4^2 are x=2sqrt(3),x=-2sqrt(3)

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x^{2} + 2^{2} = 4^{2}

x = 23, x = - 23

Decimal

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

x^{2} + 2^{2} = 4^{2}

Move

2^{2}

to the right side

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

2 x^{2} - 5 x + 2 = 1

9 n^{2} - 12 n + 4 = 0

(x + 6)^{2} = 2 x^{2} + 9 x + 18

x^{2} + 10 x - 1 = 0

2 x^{2} - 4 x + 1

What are the solutions to the equation x^2+2^2=4^2 ?
The solutions to the equation x^2+2^2=4^2 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of x^2+2^2=4^2
The zeros of x^2+2^2=4^2 are x=2sqrt(3),x=-2sqrt(3)