What are the solutions to the equation factor 2x^2-7x+3=0 ?

The solutions to the equation factor 2x^2-7x+3=0 are x= 1/2 ,x=3

Find the zeros of factor 2x^2-7x+3=0

The zeros of factor 2x^2-7x+3=0 are x= 1/2 ,x=3

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2 x^{2} - 7 x + 3 = 0

x = \frac{1}{2}, x = 3

Decimal

x = 0.5, x = 3

Solution steps

2 x^{2} - 7 x + 3 = 0

Factor

2 x^{2} - 7 x + 3 : (2 x - 1) (x - 3)

(2 x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x - 3 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 3

4 x^{2} - 1 = 0

2 y^{2} - 8 y - 3 = 0

- 4 n (n - 2) = 6 (n + 3) - 11 n^{2}

2 (x + 2)^{2} = 72

- x^{2} + 7 x - 8 = 0

What are the solutions to the equation factor 2x^2-7x+3=0 ?
The solutions to the equation factor 2x^2-7x+3=0 are x= 1/2 ,x=3
Find the zeros of factor 2x^2-7x+3=0
The zeros of factor 2x^2-7x+3=0 are x= 1/2 ,x=3