What are the solutions to the equation -x^2+7x-8=0 ?

The solutions to the equation -x^2+7x-8=0 are x=(7-sqrt(17))/2 ,x=(7+sqrt(17))/2

Find the zeros of -x^2+7x-8=0

The zeros of -x^2+7x-8=0 are x=(7-sqrt(17))/2 ,x=(7+sqrt(17))/2

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- x^{2} + 7 x - 8 = 0

x = \frac{7 - 17}{2}, x = \frac{7 + 17}{2}

Decimal

x = 1.43844 \dots, x = 5.56155 \dots

Solution steps

- x^{2} + 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 8) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 ( - 1 )}, x_{2} = \frac{- 7 - 17}{2 ( - 1 )}

x = \frac{- 7 + 17}{2 ( - 1 )} : \frac{7 - 17}{2}

x = \frac{- 7 - 17}{2 ( - 1 )} : \frac{7 + 17}{2}

The solutions to the quadratic equation are:

x = \frac{7 - 17}{2}, x = \frac{7 + 17}{2}

- x^{2} + 2 x = x + 4

x^{2} - 3 = x - 2

n^{2} - 12 n - 107 = - 8

s^{2} + 2 s - 1 = 0

3 x^{2} - 108 x = 0

What are the solutions to the equation -x^2+7x-8=0 ?
The solutions to the equation -x^2+7x-8=0 are x=(7-sqrt(17))/2 ,x=(7+sqrt(17))/2
Find the zeros of -x^2+7x-8=0
The zeros of -x^2+7x-8=0 are x=(7-sqrt(17))/2 ,x=(7+sqrt(17))/2