What are the solutions to the equation s^2+2s-1=0 ?

The solutions to the equation s^2+2s-1=0 are s=-1+sqrt(2),s=-1-sqrt(2)

Find the zeros of s^2+2s-1=0

The zeros of s^2+2s-1=0 are s=-1+sqrt(2),s=-1-sqrt(2)

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s^{2} + 2 s - 1 = 0

s = - 1 + 2, s = - 1 - 2

Decimal

s = 0.41421 \dots, s = - 2.41421 \dots

Solution steps

s^{2} + 2 s - 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

s_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

s = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

s = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

s = - 1 + 2, s = - 1 - 2

3 x^{2} - 108 x = 0

4 x - 5 x^{2} = 0

4 x^{2} - 3 x = - 2

x^{2} + 11 x = - 24

9 x^{2} - 18 x + 29 = 0

What are the solutions to the equation s^2+2s-1=0 ?
The solutions to the equation s^2+2s-1=0 are s=-1+sqrt(2),s=-1-sqrt(2)
Find the zeros of s^2+2s-1=0
The zeros of s^2+2s-1=0 are s=-1+sqrt(2),s=-1-sqrt(2)