What are the solutions to the equation 2200+35x+x^2=130x ?

The solutions to the equation 2200+35x+x^2=130x are x=55,x=40

Find the zeros of 2200+35x+x^2=130x

The zeros of 2200+35x+x^2=130x are x=55,x=40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2200 + 35 x + x^{2} = 130 x

x = 55, x = 40

Solution steps

2200 + 35 x + x^{2} = 130 x

Move

130 x

to the left side

x^{2} - 95 x + 2200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 95 ) \pm ( - 95 ) ^{2} - 4 \cdot 1 \cdot 2200}{2 \cdot 1}

(- 95)^{2} - 4 \cdot 1 \cdot 2200 = 15

x_{1, 2} = \frac{- ( - 95 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 95 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 95 ) - 15}{2 \cdot 1}

x = \frac{- ( - 95 ) + 15}{2 \cdot 1} : 55

x = \frac{- ( - 95 ) - 15}{2 \cdot 1} : 40

The solutions to the quadratic equation are:

x = 55, x = 40

6 p^{2} = 13 p - 5

(y - 1)^{2} = 0

(x - 3)^{2} = - 8

833.6 = - 0.6 q^{2} + 9.6 q + 450

s^{2} - 7 s + 10 = 0

What are the solutions to the equation 2200+35x+x^2=130x ?
The solutions to the equation 2200+35x+x^2=130x are x=55,x=40
Find the zeros of 2200+35x+x^2=130x
The zeros of 2200+35x+x^2=130x are x=55,x=40