What are the solutions to the equation (x+2)(x-2)-3x=0 ?

The solutions to the equation (x+2)(x-2)-3x=0 are x=4,x=-1

Find the zeros of (x+2)(x-2)-3x=0

The zeros of (x+2)(x-2)-3x=0 are x=4,x=-1

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(x + 2) (x - 2) - 3 x = 0

x = 4, x = - 1

Solution steps

(x + 2) (x - 2) - 3 x = 0

Expand

(x + 2) (x - 2) - 3 x : x^{2} - 4 - 3 x

x^{2} - 4 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

5 x^{2} + 6 = - 19 b + 2 b^{2}

x^{2} + 18 = 9

(4 m + 8) (m - 3) = 0

15 x^{2} - 26 x - 57 = 0

x, x^{2} + k x + 16 = 0

What are the solutions to the equation (x+2)(x-2)-3x=0 ?
The solutions to the equation (x+2)(x-2)-3x=0 are x=4,x=-1
Find the zeros of (x+2)(x-2)-3x=0
The zeros of (x+2)(x-2)-3x=0 are x=4,x=-1