What are the solutions to the equation (4m+8)(m-3)=0 ?

The solutions to the equation (4m+8)(m-3)=0 are m=-2,m=3

Find the zeros of (4m+8)(m-3)=0

The zeros of (4m+8)(m-3)=0 are m=-2,m=3

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(4 m + 8) (m - 3) = 0

m = - 2, m = 3

Solution steps

(4 m + 8) (m - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 m + 8 = 0 or m - 3 = 0

Solve

4 m + 8 = 0 : m = - 2

Solve

m - 3 = 0 : m = 3

The solutions to the quadratic equation are:

m = - 2, m = 3

15 x^{2} - 26 x - 57 = 0

x, x^{2} + k x + 16 = 0

x^{2} + 19 = 0

y, z = x^{3} - 2 y^{2} + 2 x y

a x^{2} + 4 x - a x - 4 = 0

What are the solutions to the equation (4m+8)(m-3)=0 ?
The solutions to the equation (4m+8)(m-3)=0 are m=-2,m=3
Find the zeros of (4m+8)(m-3)=0
The zeros of (4m+8)(m-3)=0 are m=-2,m=3