What are the solutions to the equation -5x^2+3x+1=0 ?

The solutions to the equation -5x^2+3x+1=0 are x=-(-3+sqrt(29))/(10),x=(3+sqrt(29))/(10)

Find the zeros of -5x^2+3x+1=0

The zeros of -5x^2+3x+1=0 are x=-(-3+sqrt(29))/(10),x=(3+sqrt(29))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} + 3 x + 1 = 0

x = - \frac{- 3 + 29}{10}, x = \frac{3 + 29}{10}

Decimal Notation

x = - 0.23851 \dots, x = 0.83851 \dots

Solution steps

- 5 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 5 ) \cdot 1}{2 ( - 5 )}

3^{2} - 4 (- 5) \cdot 1 = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 ( - 5 )}, x_{2} = \frac{- 3 - 29}{2 ( - 5 )}

x = \frac{- 3 + 29}{2 ( - 5 )} : - \frac{- 3 + 29}{10}

x = \frac{- 3 - 29}{2 ( - 5 )} : \frac{3 + 29}{10}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 29}{10}, x = \frac{3 + 29}{10}

x^{2} - 24 x + 81 = 0

x^{2} + (13 - x)^{2} = 109

x^{2} + 4 x = - 11

3 x^{2} = 18 \frac{3}{4}

(2 x + 3) (x + 1) = (x + 2) (x - 1) + 2

What are the solutions to the equation -5x^2+3x+1=0 ?
The solutions to the equation -5x^2+3x+1=0 are x=-(-3+sqrt(29))/(10),x=(3+sqrt(29))/(10)
Find the zeros of -5x^2+3x+1=0
The zeros of -5x^2+3x+1=0 are x=-(-3+sqrt(29))/(10),x=(3+sqrt(29))/(10)