What are the solutions to the equation x^2+4x=-11 ?

The solutions to the equation x^2+4x=-11 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

Find the zeros of x^2+4x=-11

The zeros of x^2+4x=-11 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

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x^{2} + 4 x = - 11

x = - 2 + 7 i, x = - 2 - 7 i

Solution steps

x^{2} + 4 x = - 11

Move

11

to the left side

x^{2} + 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 11 : 27 i

x_{1, 2} = \frac{- 4 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7 i}{2 \cdot 1}

x = \frac{- 4 + 2 7 i}{2 \cdot 1} : - 2 + 7 i

x = \frac{- 4 - 2 7 i}{2 \cdot 1} : - 2 - 7 i

The solutions to the quadratic equation are:

x = - 2 + 7 i, x = - 2 - 7 i

3 x^{2} = 18 \frac{3}{4}

(2 x + 3) (x + 1) = (x + 2) (x - 1) + 2

5 x^{2} + 2 x - 8 = 0

3 x^{2} + 11 = 0

- 2 x = x^{2} + 1

What are the solutions to the equation x^2+4x=-11 ?
The solutions to the equation x^2+4x=-11 are x=-2+sqrt(7)i,x=-2-sqrt(7)i
Find the zeros of x^2+4x=-11
The zeros of x^2+4x=-11 are x=-2+sqrt(7)i,x=-2-sqrt(7)i