What are the solutions to the equation 8w^2+10w-3=0 ?

The solutions to the equation 8w^2+10w-3=0 are w= 1/4 ,w=-3/2

Find the zeros of 8w^2+10w-3=0

The zeros of 8w^2+10w-3=0 are w= 1/4 ,w=-3/2

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8 w^{2} + 10 w - 3 = 0

w = \frac{1}{4}, w = - \frac{3}{2}

Decimal Notation

w = 0.25, w = - 1.5

Solution steps

8 w^{2} + 10 w - 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

1 0^{2} - 4 \cdot 8 (- 3) = 14

w_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 8}

Separate the solutions

w_{1} = \frac{- 10 + 14}{2 \cdot 8}, w_{2} = \frac{- 10 - 14}{2 \cdot 8}

w = \frac{- 10 + 14}{2 \cdot 8} : \frac{1}{4}

w = \frac{- 10 - 14}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

w = \frac{1}{4}, w = - \frac{3}{2}

64 x^{2} = 81

(x - 5)^{2} = - 16

989 - 264 x + 12 x^{2} = 0

x, f = \frac{3 x ^{2} - 3 x - 60}{h}

x^{2} - 10 x - 5 = 9

What are the solutions to the equation 8w^2+10w-3=0 ?
The solutions to the equation 8w^2+10w-3=0 are w= 1/4 ,w=-3/2
Find the zeros of 8w^2+10w-3=0
The zeros of 8w^2+10w-3=0 are w= 1/4 ,w=-3/2