What are the solutions to the equation 4-x^2-4+4x=0 ?

The solutions to the equation 4-x^2-4+4x=0 are x=0,x=4

Find the zeros of 4-x^2-4+4x=0

The zeros of 4-x^2-4+4x=0 are x=0,x=4

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4 - x^{2} - 4 + 4 x = 0

x = 0, x = 4

Solution steps

4 - x^{2} - 4 + 4 x = 0

Refine

- x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4}{2 ( - 1 )}

x = \frac{- 4 + 4}{2 ( - 1 )} : 0

x = \frac{- 4 - 4}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

a^{2} + 8 a + 7 = 0

x^{2} - 16

t, h = - \frac{1}{2} a t^{2} + 1

\frac{14}{15} x^{2} - 9 - \frac{11}{2} x = 0

m^{2} - 8 = 0

What are the solutions to the equation 4-x^2-4+4x=0 ?
The solutions to the equation 4-x^2-4+4x=0 are x=0,x=4
Find the zeros of 4-x^2-4+4x=0
The zeros of 4-x^2-4+4x=0 are x=0,x=4