What are the solutions to the equation (x-0.6)(3x-1.4)= 26/150 ?

The solutions to the equation (x-0.6)(3x-1.4)= 26/150 are x=(8+sqrt(14))/(15),x=(8-sqrt(14))/(15)

Find the zeros of (x-0.6)(3x-1.4)= 26/150

The zeros of (x-0.6)(3x-1.4)= 26/150 are x=(8+sqrt(14))/(15),x=(8-sqrt(14))/(15)

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(x - 0.6) (3 x - 1.4) = \frac{26}{150}

x = \frac{8 + 14}{15}, x = \frac{8 - 14}{15}

Decimal Notation

x = 0.78277 \dots, x = 0.28388 \dots

Solution steps

(x - 0.6) (3 x - 1.4) = \frac{26}{150}

Multiply both sides by

150

150 (x - 0.6) (3 x - 1.4) = 26

Expand

150 (x - 0.6) (3 x - 1.4) : 450 x^{2} - 480 x + 126

450 x^{2} - 480 x + 126 = 26

Move

26

to the left side

450 x^{2} - 480 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 480 ) \pm ( - 480 ) ^{2} - 4 \cdot 450 \cdot 100}{2 \cdot 450}

(- 480)^{2} - 4 \cdot 450 \cdot 100 = 6014

x_{1, 2} = \frac{- ( - 480 ) \pm 60 14}{2 \cdot 450}

Separate the solutions

x_{1} = \frac{- ( - 480 ) + 60 14}{2 \cdot 450}, x_{2} = \frac{- ( - 480 ) - 60 14}{2 \cdot 450}

x = \frac{- ( - 480 ) + 60 14}{2 \cdot 450} : \frac{8 + 14}{15}

x = \frac{- ( - 480 ) - 60 14}{2 \cdot 450} : \frac{8 - 14}{15}

The solutions to the quadratic equation are:

x = \frac{8 + 14}{15}, x = \frac{8 - 14}{15}

3 x^{2} - 6 x + 1 = 12

x^{2} - \frac{1}{2} x + \frac{1}{16} = 0

x^{2} - x - 32 = 0

4 - 4 x^{2} + 15 x = 0

m^{2} + 12 m = 3

What are the solutions to the equation (x-0.6)(3x-1.4)= 26/150 ?
The solutions to the equation (x-0.6)(3x-1.4)= 26/150 are x=(8+sqrt(14))/(15),x=(8-sqrt(14))/(15)
Find the zeros of (x-0.6)(3x-1.4)= 26/150
The zeros of (x-0.6)(3x-1.4)= 26/150 are x=(8+sqrt(14))/(15),x=(8-sqrt(14))/(15)