What are the solutions to the equation x^2-24x+96=0 ?

The solutions to the equation x^2-24x+96=0 are x=4(3+sqrt(3)),x=4(3-sqrt(3))

Find the zeros of x^2-24x+96=0

The zeros of x^2-24x+96=0 are x=4(3+sqrt(3)),x=4(3-sqrt(3))

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x^{2} - 24 x + 96 = 0

x = 4 (3 + 3), x = 4 (3 - 3)

Decimal Notation

x = 18.92820 \dots, x = 5.07179 \dots

Solution steps

x^{2} - 24 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 96}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 96 = 83

x_{1, 2} = \frac{- ( - 24 ) \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 3}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 8 3}{2 \cdot 1}

x = \frac{- ( - 24 ) + 8 3}{2 \cdot 1} : 4 (3 + 3)

x = \frac{- ( - 24 ) - 8 3}{2 \cdot 1} : 4 (3 - 3)

The solutions to the quadratic equation are:

x = 4 (3 + 3), x = 4 (3 - 3)

X^{2} - 81 = 0

2 x^{2} + x - 3 = 0

4 v^{2} + 12 v = 0

5 + 6 x - x^{2} = 0

2 x^{2} - 6 x + 5

What are the solutions to the equation x^2-24x+96=0 ?
The solutions to the equation x^2-24x+96=0 are x=4(3+sqrt(3)),x=4(3-sqrt(3))
Find the zeros of x^2-24x+96=0
The zeros of x^2-24x+96=0 are x=4(3+sqrt(3)),x=4(3-sqrt(3))