What are the solutions to the equation 3x^2+5x=12 ?

The solutions to the equation 3x^2+5x=12 are x= 4/3 ,x=-3

Find the zeros of 3x^2+5x=12

The zeros of 3x^2+5x=12 are x= 4/3 ,x=-3

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3 x^{2} + 5 x = 12

x = \frac{4}{3}, x = - 3

Decimal Notation

x = 1.33333 \dots, x = - 3

Solution steps

3 x^{2} + 5 x = 12

Move

12

to the left side

3 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 12) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 3}, x_{2} = \frac{- 5 - 13}{2 \cdot 3}

x = \frac{- 5 + 13}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 5 - 13}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 3

0 = 2 x^{2} - 8 x - 24

x^{2} + 4 x - 12 = 0

- 13 y - (y - 4) 2 + 8 (2 y - 3) = 8 - (y + 5) (y - 5) - 10 (y + 1)

x^{2} - 37 x + 311 = 0

g = 10 + 0.9 v - 0.01 v^{2}

What are the solutions to the equation 3x^2+5x=12 ?
The solutions to the equation 3x^2+5x=12 are x= 4/3 ,x=-3
Find the zeros of 3x^2+5x=12
The zeros of 3x^2+5x=12 are x= 4/3 ,x=-3