What are the solutions to the equation 24^2+45^2=c^2 ?

The solutions to the equation 24^2+45^2=c^2 are c=51,c=-51

Find the zeros of 24^2+45^2=c^2

The zeros of 24^2+45^2=c^2 are c=51,c=-51

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 4^{2} + 4 5^{2} = c^{2}

c = 51, c = - 51

Solution steps

2 4^{2} + 4 5^{2} = c^{2}

Switch sides

c^{2} = 2 4^{2} + 4 5^{2}

Simplify

2 4^{2} + 4 5^{2} : 2601

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 2601, c = - 2601

2601 = 51

- 2601 = - 51

c = 51, c = - 51

7 t^{2} + 28 t + 56 = 0

9 x - 9 = - 4 x^{2}

x^{2} - 40 x + 144 = 0

x^{2} - 84 = - 3

- 7 x^{2} + 23 x = 180

What are the solutions to the equation 24^2+45^2=c^2 ?
The solutions to the equation 24^2+45^2=c^2 are c=51,c=-51
Find the zeros of 24^2+45^2=c^2
The zeros of 24^2+45^2=c^2 are c=51,c=-51