What are the solutions to the equation 3x^2+4x=10 ?

The solutions to the equation 3x^2+4x=10 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3

Find the zeros of 3x^2+4x=10

The zeros of 3x^2+4x=10 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3

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3 x^{2} + 4 x = 10

x = \frac{- 2 + 34}{3}, x = - \frac{2 + 34}{3}

Decimal Notation

x = 1.27698 \dots, x = - 2.61031 \dots

Solution steps

3 x^{2} + 4 x = 10

Move

10

to the left side

3 x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 10) = 234

x_{1, 2} = \frac{- 4 \pm 2 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 34}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 34}{2 \cdot 3}

x = \frac{- 4 + 2 34}{2 \cdot 3} : \frac{- 2 + 34}{3}

x = \frac{- 4 - 2 34}{2 \cdot 3} : - \frac{2 + 34}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 34}{3}, x = - \frac{2 + 34}{3}

3 x^{2} + 2 x = - 3 x + 5

8 y^{2} - 16 y = 0

g (n) = n^{2} + 2, g (3)

x^{2} - (a - 2) x - 2 a^{2} + 5 a - 3 = 0

x^{2} - 6 x - 3 = 0

What are the solutions to the equation 3x^2+4x=10 ?
The solutions to the equation 3x^2+4x=10 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3
Find the zeros of 3x^2+4x=10
The zeros of 3x^2+4x=10 are x=(-2+sqrt(34))/3 ,x=-(2+sqrt(34))/3