What are the solutions to the equation 2x^2+0.2x-0.12=0 ?

The solutions to the equation 2x^2+0.2x-0.12=0 are x= 1/5 ,x=-3/10

Find the zeros of 2x^2+0.2x-0.12=0

The zeros of 2x^2+0.2x-0.12=0 are x= 1/5 ,x=-3/10

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2 x^{2} + 0.2 x - 0.12 = 0

x = \frac{1}{5}, x = - \frac{3}{10}

Decimal Notation

x = 0.2, x = - 0.3

Solution steps

2 x^{2} + 0.2 x - 0.12 = 0

Multiply both sides by

100

200 x^{2} + 20 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 200 ( - 12 )}{2 \cdot 200}

2 0^{2} - 4 \cdot 200 (- 12) = 100

x_{1, 2} = \frac{- 20 \pm 100}{2 \cdot 200}

Separate the solutions

x_{1} = \frac{- 20 + 100}{2 \cdot 200}, x_{2} = \frac{- 20 - 100}{2 \cdot 200}

x = \frac{- 20 + 100}{2 \cdot 200} : \frac{1}{5}

x = \frac{- 20 - 100}{2 \cdot 200} : - \frac{3}{10}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{3}{10}

6 x^{2} + 2 x + 8 = 0

24 = 4 + 37 x - 16 x^{2}

3 x^{2} + x = 10

x^{2} + 16 x = - 62

(x - 2) (- x - 2) = 20

What are the solutions to the equation 2x^2+0.2x-0.12=0 ?
The solutions to the equation 2x^2+0.2x-0.12=0 are x= 1/5 ,x=-3/10
Find the zeros of 2x^2+0.2x-0.12=0
The zeros of 2x^2+0.2x-0.12=0 are x= 1/5 ,x=-3/10