What are the solutions to the equation (x-2)(-x-2)=20 ?

The solutions to the equation (x-2)(-x-2)=20 are x=-4i,x=4i

Find the zeros of (x-2)(-x-2)=20

The zeros of (x-2)(-x-2)=20 are x=-4i,x=4i

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(x - 2) (- x - 2) = 20

x = - 4 i, x = 4 i

Solution steps

(x - 2) (- x - 2) = 20

Expand

(x - 2) (- x - 2) : - x^{2} + 4

- x^{2} + 4 = 20

Move

20

to the left side

- x^{2} - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

Simplify

0^{2} - 4 (- 1) (- 16) : 8 i

x_{1, 2} = \frac{- 0 \pm 8 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 0 + 8 i}{2 ( - 1 )}, x_{2} = \frac{- 0 - 8 i}{2 ( - 1 )}

x = \frac{- 0 + 8 i}{2 ( - 1 )} : - 4 i

x = \frac{- 0 - 8 i}{2 ( - 1 )} : 4 i

The solutions to the quadratic equation are:

x = - 4 i, x = 4 i

2 x^{2} - 4 x - 13 = 0

1 x^{2} + 2 x + 4 = 0

x^{2} - 15 x + 25 = 0

\frac{1}{5} x^{2} + 2 x + 5 = 0

6 x^{2} + 10 x = 4 - 10 x - 6 x^{2}

What are the solutions to the equation (x-2)(-x-2)=20 ?
The solutions to the equation (x-2)(-x-2)=20 are x=-4i,x=4i
Find the zeros of (x-2)(-x-2)=20
The zeros of (x-2)(-x-2)=20 are x=-4i,x=4i