What are the solutions to the equation solvefor x,9x^2-4y^2+18x-16y=7 ?

The solutions to the equation solvefor x,9x^2-4y^2+18x-16y=7 are x=(2y+1)/3 ,x=-(2y+7)/3

Find the zeros of solvefor x,9x^2-4y^2+18x-16y=7

The zeros of solvefor x,9x^2-4y^2+18x-16y=7 are x=(2y+1)/3 ,x=-(2y+7)/3

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solve for

x, 9 x^{2} - 4 y^{2} + 18 x - 16 y = 7

x = \frac{2 y + 1}{3}, x = - \frac{2 y + 7}{3}

Solution steps

9 x^{2} - 4 y^{2} + 18 x - 16 y = 7

Move

7

to the left side

9 x^{2} - 4 y^{2} + 18 x - 16 y - 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} + 18 x - 4 y^{2} - 16 y - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 4 y ^{2} - 16 y - 7 )}{2 \cdot 9}

Simplify

1 8^{2} - 4 \cdot 9 (- 4 y^{2} - 16 y - 7) : 12 (y + 2)

x_{1, 2} = \frac{- 18 \pm 12 ( y + 2 )}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 12 ( y + 2 )}{2 \cdot 9}, x_{2} = \frac{- 18 - 12 ( y + 2 )}{2 \cdot 9}

x = \frac{- 18 + 12 ( y + 2 )}{2 \cdot 9} : \frac{2 y + 1}{3}

x = \frac{- 18 - 12 ( y + 2 )}{2 \cdot 9} : - \frac{2 y + 7}{3}

The solutions to the quadratic equation are:

x = \frac{2 y + 1}{3}, x = - \frac{2 y + 7}{3}

4 x^{2} + 34 x - 25 = 0

49 x^{2} - 7 x - \frac{3}{4}

5 x^{2} + 3 x + 7 = 0

(m + 4) x^{2} - 2 m x + 2 = 0

- t^{2} + 78 t + 460 = 1581

What are the solutions to the equation solvefor x,9x^2-4y^2+18x-16y=7 ?
The solutions to the equation solvefor x,9x^2-4y^2+18x-16y=7 are x=(2y+1)/3 ,x=-(2y+7)/3
Find the zeros of solvefor x,9x^2-4y^2+18x-16y=7
The zeros of solvefor x,9x^2-4y^2+18x-16y=7 are x=(2y+1)/3 ,x=-(2y+7)/3