What are the solutions to the equation 6^2=4^2+x^2 ?

The solutions to the equation 6^2=4^2+x^2 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of 6^2=4^2+x^2

The zeros of 6^2=4^2+x^2 are x=2sqrt(5),x=-2sqrt(5)

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6^{2} = 4^{2} + x^{2}

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

6^{2} = 4^{2} + x^{2}

Switch sides

4^{2} + x^{2} = 6^{2}

Move

4^{2}

to the right side

x^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

16 x^{2} - 56 x + 51 = 0

8 x^{2} + 2 = - 8 x

2 x^{2} - \frac{1}{3} x

0 = 2 x^{2} + 4 x + 2

x, z = 4 + x^{2} + y^{2}

What are the solutions to the equation 6^2=4^2+x^2 ?
The solutions to the equation 6^2=4^2+x^2 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of 6^2=4^2+x^2
The zeros of 6^2=4^2+x^2 are x=2sqrt(5),x=-2sqrt(5)