What are the solutions to the equation z^2+3z-2=0 ?

The solutions to the equation z^2+3z-2=0 are z=(-3+sqrt(17))/2 ,z=(-3-sqrt(17))/2

Find the zeros of z^2+3z-2=0

The zeros of z^2+3z-2=0 are z=(-3+sqrt(17))/2 ,z=(-3-sqrt(17))/2

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z^{2} + 3 z - 2 = 0

z = \frac{- 3 + 17}{2}, z = \frac{- 3 - 17}{2}

Decimal Notation

z = 0.56155 \dots, z = - 3.56155 \dots

Solution steps

z^{2} + 3 z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

z_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 3 + 17}{2 \cdot 1}, z_{2} = \frac{- 3 - 17}{2 \cdot 1}

z = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

z = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

z = \frac{- 3 + 17}{2}, z = \frac{- 3 - 17}{2}

0 = 2 x - x^{2}

q, p = 2 + \frac{1}{5} q + \frac{1}{20} q^{2}

4 x^{2} - 3 x = 2

(10 - x) (- 12 - x) + 40 = 0

x (4 x - 1) = 3 x (x - 2) + 6

What are the solutions to the equation z^2+3z-2=0 ?
The solutions to the equation z^2+3z-2=0 are z=(-3+sqrt(17))/2 ,z=(-3-sqrt(17))/2
Find the zeros of z^2+3z-2=0
The zeros of z^2+3z-2=0 are z=(-3+sqrt(17))/2 ,z=(-3-sqrt(17))/2