What are the solutions to the equation 6x^2-3x-12=0 ?

The solutions to the equation 6x^2-3x-12=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4

Find the zeros of 6x^2-3x-12=0

The zeros of 6x^2-3x-12=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4

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6 x^{2} - 3 x - 12 = 0

x = \frac{1 + 33}{4}, x = \frac{1 - 33}{4}

Decimal Notation

x = 1.68614 \dots, x = - 1.18614 \dots

Solution steps

6 x^{2} - 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

(- 3)^{2} - 4 \cdot 6 (- 12) = 333

x_{1, 2} = \frac{- ( - 3 ) \pm 3 33}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 33}{2 \cdot 6}, x_{2} = \frac{- ( - 3 ) - 3 33}{2 \cdot 6}

x = \frac{- ( - 3 ) + 3 33}{2 \cdot 6} : \frac{1 + 33}{4}

x = \frac{- ( - 3 ) - 3 33}{2 \cdot 6} : \frac{1 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 33}{4}, x = \frac{1 - 33}{4}

- 2 x^{2} - 6 x - 2 = 0

x (x + 6) = 27

30 x^{2} - 61 x + 30 = 0

x, 3 x^{2} - x y^{2} = C

x^{2} + 18 x - 243 = 0

What are the solutions to the equation 6x^2-3x-12=0 ?
The solutions to the equation 6x^2-3x-12=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4
Find the zeros of 6x^2-3x-12=0
The zeros of 6x^2-3x-12=0 are x=(1+sqrt(33))/4 ,x=(1-sqrt(33))/4