What are the solutions to the equation -2x^2-6x-2=0 ?

The solutions to the equation -2x^2-6x-2=0 are x=-(3+sqrt(5))/2 ,x=-(3-sqrt(5))/2

Find the zeros of -2x^2-6x-2=0

The zeros of -2x^2-6x-2=0 are x=-(3+sqrt(5))/2 ,x=-(3-sqrt(5))/2

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- 2 x^{2} - 6 x - 2 = 0

x = - \frac{3 + 5}{2}, x = - \frac{3 - 5}{2}

Decimal Notation

x = - 2.61803 \dots, x = - 0.38196 \dots

Solution steps

- 2 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) (- 2) = 25

x_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 5}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 5}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 5}{2 ( - 2 )} : - \frac{3 + 5}{2}

x = \frac{- ( - 6 ) - 2 5}{2 ( - 2 )} : - \frac{3 - 5}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 5}{2}, x = - \frac{3 - 5}{2}

x (x + 6) = 27

30 x^{2} - 61 x + 30 = 0

x, 3 x^{2} - x y^{2} = C

x^{2} + 18 x - 243 = 0

- 2 x^{2} - 6 x - 1 = 0

What are the solutions to the equation -2x^2-6x-2=0 ?
The solutions to the equation -2x^2-6x-2=0 are x=-(3+sqrt(5))/2 ,x=-(3-sqrt(5))/2
Find the zeros of -2x^2-6x-2=0
The zeros of -2x^2-6x-2=0 are x=-(3+sqrt(5))/2 ,x=-(3-sqrt(5))/2