What are the solutions to the equation 3x^2+5x=6 ?

The solutions to the equation 3x^2+5x=6 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6

Find the zeros of 3x^2+5x=6

The zeros of 3x^2+5x=6 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6

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3 x^{2} + 5 x = 6

x = \frac{- 5 + 97}{6}, x = \frac{- 5 - 97}{6}

Decimal Notation

x = 0.80814 \dots, x = - 2.47480 \dots

Solution steps

3 x^{2} + 5 x = 6

Move

6

to the left side

3 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 6) = 97

x_{1, 2} = \frac{- 5 \pm 97}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 97}{2 \cdot 3}, x_{2} = \frac{- 5 - 97}{2 \cdot 3}

x = \frac{- 5 + 97}{2 \cdot 3} : \frac{- 5 + 97}{6}

x = \frac{- 5 - 97}{2 \cdot 3} : \frac{- 5 - 97}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 97}{6}, x = \frac{- 5 - 97}{6}

x^{2} + 2 x - 26 = 0

x^{2} - \frac{5}{6} x + \frac{2}{3} = 0

3 x^{2} + 7 = 7 x

2 p^{2} - 5 p - 3 = 0

y^{2} - 3 = y - y^{2}

What are the solutions to the equation 3x^2+5x=6 ?
The solutions to the equation 3x^2+5x=6 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6
Find the zeros of 3x^2+5x=6
The zeros of 3x^2+5x=6 are x=(-5+sqrt(97))/6 ,x=(-5-sqrt(97))/6