What are the solutions to the equation r^2+2r-15=0 ?

The solutions to the equation r^2+2r-15=0 are r=3,r=-5

Find the zeros of r^2+2r-15=0

The zeros of r^2+2r-15=0 are r=3,r=-5

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r^{2} + 2 r - 15 = 0

r = 3, r = - 5

Solution steps

r^{2} + 2 r - 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

r_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 8}{2 \cdot 1}, r_{2} = \frac{- 2 - 8}{2 \cdot 1}

r = \frac{- 2 + 8}{2 \cdot 1} : 3

r = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

r = 3, r = - 5

x^{2} + 14 x - 14 = 0

3 x^{2} - 22 x - 16 = 0

- (x - 3)^{2} - 7 = 0

2 X^{2} - 7 X + 3 = 0

2 x (5 - 4 x) - 6 (3 x^{2} + 1) = 2 (2 x^{2} - 4)

What are the solutions to the equation r^2+2r-15=0 ?
The solutions to the equation r^2+2r-15=0 are r=3,r=-5
Find the zeros of r^2+2r-15=0
The zeros of r^2+2r-15=0 are r=3,r=-5