What are the solutions to the equation x^2+14x+49=16 ?

The solutions to the equation x^2+14x+49=16 are x=-3,x=-11

Find the zeros of x^2+14x+49=16

The zeros of x^2+14x+49=16 are x=-3,x=-11

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x^{2} + 14 x + 49 = 16

x = - 3, x = - 11

Solution steps

x^{2} + 14 x + 49 = 16

Move

16

to the left side

x^{2} + 14 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 33 = 8

x_{1, 2} = \frac{- 14 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 8}{2 \cdot 1}, x_{2} = \frac{- 14 - 8}{2 \cdot 1}

x = \frac{- 14 + 8}{2 \cdot 1} : - 3

x = \frac{- 14 - 8}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 3, x = - 11

4 x - 5 x^{2} = - 12

7 x^{2} - 4 x = - 3

2 x^{2} + 38 x + 180 = 0

3 x^{2} - 15 x = 72

6 u^{2} + 4 u + 11 = 0

What are the solutions to the equation x^2+14x+49=16 ?
The solutions to the equation x^2+14x+49=16 are x=-3,x=-11
Find the zeros of x^2+14x+49=16
The zeros of x^2+14x+49=16 are x=-3,x=-11