What are the solutions to the equation 4x(1-x)=x ?

The solutions to the equation 4x(1-x)=x are x=0,x= 3/4

Find the zeros of 4x(1-x)=x

The zeros of 4x(1-x)=x are x=0,x= 3/4

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4 x (1 - x) = x

x = 0, x = \frac{3}{4}

Decimal Notation

x = 0, x = 0.75

Solution steps

4 x (1 - x) = x

Expand

4 x (1 - x) : 4 x - 4 x^{2}

4 x - 4 x^{2} = x

Move

x

to the left side

- 4 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 4 )}, x_{2} = \frac{- 3 - 3}{2 ( - 4 )}

x = \frac{- 3 + 3}{2 ( - 4 )} : 0

x = \frac{- 3 - 3}{2 ( - 4 )} : \frac{3}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{3}{4}

x^{2} - 10 x - 20 = 0

x \frac{1}{4} x - \frac{3}{5} (x - 3) = 20

(d + 3)^{2} = 7

x^{2} - 2 x - \frac{1}{2} = 0

y^{2} - 12 y

What are the solutions to the equation 4x(1-x)=x ?
The solutions to the equation 4x(1-x)=x are x=0,x= 3/4
Find the zeros of 4x(1-x)=x
The zeros of 4x(1-x)=x are x=0,x= 3/4