What are the solutions to the equation 4x^2-9x=28 ?

The solutions to the equation 4x^2-9x=28 are x=4,x=-7/4

Find the zeros of 4x^2-9x=28

The zeros of 4x^2-9x=28 are x=4,x=-7/4

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4 x^{2} - 9 x = 28

x = 4, x = - \frac{7}{4}

Decimal Notation

x = 4, x = - 1.75

Solution steps

4 x^{2} - 9 x = 28

Move

28

to the left side

4 x^{2} - 9 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 28 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 28) = 23

x_{1, 2} = \frac{- ( - 9 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 23}{2 \cdot 4}

x = \frac{- ( - 9 ) + 23}{2 \cdot 4} : 4

x = \frac{- ( - 9 ) - 23}{2 \cdot 4} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = 4, x = - \frac{7}{4}

x^{2} + 3 x - 208 = 0

y, 2 x^{2} + 2 x y + 4 y^{2} = 5

2 x^{2} + 5 x - 3

(x - 1) (x + 2) = e

350000 = - 2200 (t - 14)^{2} + 486430

What are the solutions to the equation 4x^2-9x=28 ?
The solutions to the equation 4x^2-9x=28 are x=4,x=-7/4
Find the zeros of 4x^2-9x=28
The zeros of 4x^2-9x=28 are x=4,x=-7/4