What are the solutions to the equation x^2+3x-208=0 ?

The solutions to the equation x^2+3x-208=0 are x=13,x=-16

Find the zeros of x^2+3x-208=0

The zeros of x^2+3x-208=0 are x=13,x=-16

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x^{2} + 3 x - 208 = 0

x = 13, x = - 16

Solution steps

x^{2} + 3 x - 208 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 208 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 208) = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 \cdot 1}, x_{2} = \frac{- 3 - 29}{2 \cdot 1}

x = \frac{- 3 + 29}{2 \cdot 1} : 13

x = \frac{- 3 - 29}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 13, x = - 16

y, 2 x^{2} + 2 x y + 4 y^{2} = 5

2 x^{2} + 5 x - 3

(x - 1) (x + 2) = e

350000 = - 2200 (t - 14)^{2} + 486430

(r + 3)^{2} - 7 = 7

What are the solutions to the equation x^2+3x-208=0 ?
The solutions to the equation x^2+3x-208=0 are x=13,x=-16
Find the zeros of x^2+3x-208=0
The zeros of x^2+3x-208=0 are x=13,x=-16