What are the solutions to the equation (r+3)^2-7=7 ?

The solutions to the equation (r+3)^2-7=7 are r=sqrt(14)-3,r=-sqrt(14)-3

Find the zeros of (r+3)^2-7=7

The zeros of (r+3)^2-7=7 are r=sqrt(14)-3,r=-sqrt(14)-3

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(r + 3)^{2} - 7 = 7

r = 14 - 3, r = - 14 - 3

Decimal Notation

r = 0.74165 \dots, r = - 6.74165 \dots

Solution steps

(r + 3)^{2} - 7 = 7

Move

7

to the right side

(r + 3)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r + 3 = 14 : r = 14 - 3

Solve

r + 3 = - 14 : r = - 14 - 3

The solutions to the quadratic equation are:

r = 14 - 3, r = - 14 - 3

80 = x^{2}

x^{2} - 9 = 160

- x^{2} - 10 x + 15 = 0

(x - a + 2) (x - a + 3) = 42

- 2 x^{2} + x + 2 = 0

What are the solutions to the equation (r+3)^2-7=7 ?
The solutions to the equation (r+3)^2-7=7 are r=sqrt(14)-3,r=-sqrt(14)-3
Find the zeros of (r+3)^2-7=7
The zeros of (r+3)^2-7=7 are r=sqrt(14)-3,r=-sqrt(14)-3