What are the solutions to the equation -2x^2+x+2=0 ?

The solutions to the equation -2x^2+x+2=0 are x=-(-1+sqrt(17))/4 ,x=(1+sqrt(17))/4

Find the zeros of -2x^2+x+2=0

The zeros of -2x^2+x+2=0 are x=-(-1+sqrt(17))/4 ,x=(1+sqrt(17))/4

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- 2 x^{2} + x + 2 = 0

x = - \frac{- 1 + 17}{4}, x = \frac{1 + 17}{4}

Decimal Notation

x = - 0.78077 \dots, x = 1.28077 \dots

Solution steps

- 2 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 2}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 2 = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 ( - 2 )}, x_{2} = \frac{- 1 - 17}{2 ( - 2 )}

x = \frac{- 1 + 17}{2 ( - 2 )} : - \frac{- 1 + 17}{4}

x = \frac{- 1 - 17}{2 ( - 2 )} : \frac{1 + 17}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 17}{4}, x = \frac{1 + 17}{4}

x^{2} - 2 x + 8

20 x^{2} - 7 x = 6

(x - 4)^{2} - 20 = 0

x (x - 1) = 3

x, x^{2} + k x + 3 = 0

What are the solutions to the equation -2x^2+x+2=0 ?
The solutions to the equation -2x^2+x+2=0 are x=-(-1+sqrt(17))/4 ,x=(1+sqrt(17))/4
Find the zeros of -2x^2+x+2=0
The zeros of -2x^2+x+2=0 are x=-(-1+sqrt(17))/4 ,x=(1+sqrt(17))/4