What are the solutions to the equation (x-4)^2-20=0 ?

The solutions to the equation (x-4)^2-20=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4

Find the zeros of (x-4)^2-20=0

The zeros of (x-4)^2-20=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4

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(x - 4)^{2} - 20 = 0

x = 25 + 4, x = - 25 + 4

Decimal Notation

x = 8.47213 \dots, x = - 0.47213 \dots

Solution steps

(x - 4)^{2} - 20 = 0

Move

20

to the right side

(x - 4)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 20 : x = 25 + 4

Solve

x - 4 = - 20 : x = - 25 + 4

The solutions to the quadratic equation are:

x = 25 + 4, x = - 25 + 4

x (x - 1) = 3

x, x^{2} + k x + 3 = 0

w^{2} = 13 w

1 - 25 x^{2} = 0

(x + 2)^{2} - 1 = 4

What are the solutions to the equation (x-4)^2-20=0 ?
The solutions to the equation (x-4)^2-20=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4
Find the zeros of (x-4)^2-20=0
The zeros of (x-4)^2-20=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4