What are the solutions to the equation 1-25x^2=0 ?

The solutions to the equation 1-25x^2=0 are x= 1/5 ,x=-1/5

Find the zeros of 1-25x^2=0

The zeros of 1-25x^2=0 are x= 1/5 ,x=-1/5

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1 - 25 x^{2} = 0

x = \frac{1}{5}, x = - \frac{1}{5}

Decimal Notation

x = 0.2, x = - 0.2

Solution steps

1 - 25 x^{2} = 0

Move

1

to the right side

- 25 x^{2} = - 1

Divide both sides by

- 25

x^{2} = \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{25}, x = - \frac{1}{25}

\frac{1}{25} = \frac{1}{5}

- \frac{1}{25} = - \frac{1}{5}

x = \frac{1}{5}, x = - \frac{1}{5}

(x + 2)^{2} - 1 = 4

0 = - 24 x^{2} + 16

x, f = x^{2} + k x + 2

x^{2} + 2 x - 100 = 0

x^{2} + 12 x + 3 = 7

What are the solutions to the equation 1-25x^2=0 ?
The solutions to the equation 1-25x^2=0 are x= 1/5 ,x=-1/5
Find the zeros of 1-25x^2=0
The zeros of 1-25x^2=0 are x= 1/5 ,x=-1/5