What are the solutions to the equation 0=-24x^2+16 ?

The solutions to the equation 0=-24x^2+16 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of 0=-24x^2+16

The zeros of 0=-24x^2+16 are x=sqrt(2/3),x=-sqrt(2/3)

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0 = - 24 x^{2} + 16

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

0 = - 24 x^{2} + 16

Switch sides

- 24 x^{2} + 16 = 0

Move

16

to the right side

- 24 x^{2} = - 16

Divide both sides by

- 24

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

x, f = x^{2} + k x + 2

x^{2} + 2 x - 100 = 0

x^{2} + 12 x + 3 = 7

5 b^{2} + b - 2 = 0

3 x^{2} - a = 0

What are the solutions to the equation 0=-24x^2+16 ?
The solutions to the equation 0=-24x^2+16 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of 0=-24x^2+16
The zeros of 0=-24x^2+16 are x=sqrt(2/3),x=-sqrt(2/3)