What are the solutions to the equation completesquare x^2+12x+3=7 ?

The solutions to the equation completesquare x^2+12x+3=7 are x=2sqrt(10)-6,x=-2sqrt(10)-6

Find the zeros of completesquare x^2+12x+3=7

The zeros of completesquare x^2+12x+3=7 are x=2sqrt(10)-6,x=-2sqrt(10)-6

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x^{2} + 12 x + 3 = 7

x = 210 - 6, x = - 210 - 6

Decimal Notation

x = 0.32455 \dots, x = - 12.32455 \dots

Solution steps

x^{2} + 12 x + 3 = 7

Move

3

to the right side

x^{2} + 12 x = 4

Rewrite in the form

(x + a)^{2} = b

(x + 6)^{2} = 40

For

the solutions are

f (x) = a, - a

Solve

x + 6 = 40 : x = 210 - 6

Solve

x + 6 = - 40 : x = - 210 - 6

The solutions to the quadratic equation are:

x = 210 - 6, x = - 210 - 6

5 b^{2} + b - 2 = 0

3 x^{2} - a = 0

4 s^{2} - 4 s - 3 = 0

4 x^{2} = - 28

(x - 2)^{2} + 40 = - 5

What are the solutions to the equation completesquare x^2+12x+3=7 ?
The solutions to the equation completesquare x^2+12x+3=7 are x=2sqrt(10)-6,x=-2sqrt(10)-6
Find the zeros of completesquare x^2+12x+3=7
The zeros of completesquare x^2+12x+3=7 are x=2sqrt(10)-6,x=-2sqrt(10)-6