What are the solutions to the equation 4s^2-4s-3=0 ?

The solutions to the equation 4s^2-4s-3=0 are s= 3/2 ,s=-1/2

Find the zeros of 4s^2-4s-3=0

The zeros of 4s^2-4s-3=0 are s= 3/2 ,s=-1/2

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4 s^{2} - 4 s - 3 = 0

s = \frac{3}{2}, s = - \frac{1}{2}

Decimal Notation

s = 1.5, s = - 0.5

Solution steps

4 s^{2} - 4 s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

s_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, s_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

s = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

s = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

s = \frac{3}{2}, s = - \frac{1}{2}

4 x^{2} = - 28

(x - 2)^{2} + 40 = - 5

3 (x - 5)^{2} = 12

a^{2} - 12 a + 36 = 0

4 x^{2} = 324

What are the solutions to the equation 4s^2-4s-3=0 ?
The solutions to the equation 4s^2-4s-3=0 are s= 3/2 ,s=-1/2
Find the zeros of 4s^2-4s-3=0
The zeros of 4s^2-4s-3=0 are s= 3/2 ,s=-1/2