What are the solutions to the equation 4x^2=-28 ?

The solutions to the equation 4x^2=-28 are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of 4x^2=-28

The zeros of 4x^2=-28 are x=sqrt(7)i,x=-sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} = - 28

x = 7 i, x = - 7 i

Solution steps

4 x^{2} = - 28

Divide both sides by

4

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

(x - 2)^{2} + 40 = - 5

3 (x - 5)^{2} = 12

a^{2} - 12 a + 36 = 0

4 x^{2} = 324

4 x^{2} - 36 x = - 85 - 85

What are the solutions to the equation 4x^2=-28 ?
The solutions to the equation 4x^2=-28 are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of 4x^2=-28
The zeros of 4x^2=-28 are x=sqrt(7)i,x=-sqrt(7)i