What are the solutions to the equation 4x^2-36x=-85-85 ?

The solutions to the equation 4x^2-36x=-85-85 are x= 9/2+i(sqrt(89))/2 ,x= 9/2-i(sqrt(89))/2

Find the zeros of 4x^2-36x=-85-85

The zeros of 4x^2-36x=-85-85 are x= 9/2+i(sqrt(89))/2 ,x= 9/2-i(sqrt(89))/2

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4 x^{2} - 36 x = - 85 - 85

x = \frac{9}{2} + i \frac{89}{2}, x = \frac{9}{2} - i \frac{89}{2}

Solution steps

4 x^{2} - 36 x = - 85 - 85

Refine

4 x^{2} - 36 x = - 170

Move

170

to the left side

4 x^{2} - 36 x + 170 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 170}{2 \cdot 4}

Simplify

(- 36)^{2} - 4 \cdot 4 \cdot 170 : 489 i

x_{1, 2} = \frac{- ( - 36 ) \pm 4 89 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 4 89 i}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 4 89 i}{2 \cdot 4}

x = \frac{- ( - 36 ) + 4 89 i}{2 \cdot 4} : \frac{9}{2} + i \frac{89}{2}

x = \frac{- ( - 36 ) - 4 89 i}{2 \cdot 4} : \frac{9}{2} - i \frac{89}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{89}{2}, x = \frac{9}{2} - i \frac{89}{2}

3 x^{2} - 24 x + 32 = 0

x^{2} - 9 = - 2 x

x^{2} - 9 = - 4 x

10 x - x^{2}

9 (x - 1)^{2} = 7

What are the solutions to the equation 4x^2-36x=-85-85 ?
The solutions to the equation 4x^2-36x=-85-85 are x= 9/2+i(sqrt(89))/2 ,x= 9/2-i(sqrt(89))/2
Find the zeros of 4x^2-36x=-85-85
The zeros of 4x^2-36x=-85-85 are x= 9/2+i(sqrt(89))/2 ,x= 9/2-i(sqrt(89))/2