What are the solutions to the equation x^2-9=-4x ?

The solutions to the equation x^2-9=-4x are x=-2+sqrt(13),x=-2-sqrt(13)

Find the zeros of x^2-9=-4x

The zeros of x^2-9=-4x are x=-2+sqrt(13),x=-2-sqrt(13)

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x^{2} - 9 = - 4 x

x = - 2 + 13, x = - 2 - 13

Decimal Notation

x = 1.60555 \dots, x = - 5.60555 \dots

Solution steps

x^{2} - 9 = - 4 x

Move

4 x

to the left side

x^{2} - 9 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 9) = 213

x_{1, 2} = \frac{- 4 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 13}{2 \cdot 1}

x = \frac{- 4 + 2 13}{2 \cdot 1} : - 2 + 13

x = \frac{- 4 - 2 13}{2 \cdot 1} : - 2 - 13

The solutions to the quadratic equation are:

x = - 2 + 13, x = - 2 - 13

10 x - x^{2}

9 (x - 1)^{2} = 7

\frac{5}{6} x^{2} - \frac{2}{3} x = \frac{1}{3}

y, x^{3} + x^{2} y + y^{2} = 0

5 x^{2} = 36 x + 32

What are the solutions to the equation x^2-9=-4x ?
The solutions to the equation x^2-9=-4x are x=-2+sqrt(13),x=-2-sqrt(13)
Find the zeros of x^2-9=-4x
The zeros of x^2-9=-4x are x=-2+sqrt(13),x=-2-sqrt(13)