What are the solutions to the equation 9(x-1)^2=7 ?

The solutions to the equation 9(x-1)^2=7 are x=(sqrt(7))/3+1,x=-(sqrt(7))/3+1

Find the zeros of 9(x-1)^2=7

The zeros of 9(x-1)^2=7 are x=(sqrt(7))/3+1,x=-(sqrt(7))/3+1

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9 (x - 1)^{2} = 7

x = \frac{7}{3} + 1, x = - \frac{7}{3} + 1

Decimal

x = 1.88191 \dots, x = 0.11808 \dots

Solution steps

9 (x - 1)^{2} = 7

Divide both sides by

9

(x - 1)^{2} = \frac{7}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{7}{9} : x = \frac{7}{3} + 1

Solve

x - 1 = - \frac{7}{9} : x = - \frac{7}{3} + 1

The solutions to the quadratic equation are:

x = \frac{7}{3} + 1, x = - \frac{7}{3} + 1

\frac{5}{6} x^{2} - \frac{2}{3} x = \frac{1}{3}

y, x^{3} + x^{2} y + y^{2} = 0

5 x^{2} = 36 x + 32

x^{2} - 12 x + 36 = 3 x

x^{2} + 2 x - 50 = 0

What are the solutions to the equation 9(x-1)^2=7 ?
The solutions to the equation 9(x-1)^2=7 are x=(sqrt(7))/3+1,x=-(sqrt(7))/3+1
Find the zeros of 9(x-1)^2=7
The zeros of 9(x-1)^2=7 are x=(sqrt(7))/3+1,x=-(sqrt(7))/3+1