What are the solutions to the equation x^2+2x-50=0 ?

The solutions to the equation x^2+2x-50=0 are x=-1+sqrt(51),x=-1-sqrt(51)

Find the zeros of x^2+2x-50=0

The zeros of x^2+2x-50=0 are x=-1+sqrt(51),x=-1-sqrt(51)

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x^{2} + 2 x - 50 = 0

x = - 1 + 51, x = - 1 - 51

Decimal Notation

x = 6.14142 \dots, x = - 8.14142 \dots

Solution steps

x^{2} + 2 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 50 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 50) = 251

x_{1, 2} = \frac{- 2 \pm 2 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 51}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 51}{2 \cdot 1}

x = \frac{- 2 + 2 51}{2 \cdot 1} : - 1 + 51

x = \frac{- 2 - 2 51}{2 \cdot 1} : - 1 - 51

The solutions to the quadratic equation are:

x = - 1 + 51, x = - 1 - 51

5 x^{2} + 27 x + 10 = 0

x, 3 x^{2} + k x + 3 = 0

x^{2} + 13 x = - 30

b^{2} + 13 b + 40 = 0

12 = 8 x - x^{2}

What are the solutions to the equation x^2+2x-50=0 ?
The solutions to the equation x^2+2x-50=0 are x=-1+sqrt(51),x=-1-sqrt(51)
Find the zeros of x^2+2x-50=0
The zeros of x^2+2x-50=0 are x=-1+sqrt(51),x=-1-sqrt(51)