What are the solutions to the equation 7x^2-42=-35x ?

The solutions to the equation 7x^2-42=-35x are x=1,x=-6

Find the zeros of 7x^2-42=-35x

The zeros of 7x^2-42=-35x are x=1,x=-6

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7 x^{2} - 42 = - 35 x

x = 1, x = - 6

Solution steps

7 x^{2} - 42 = - 35 x

Move

35 x

to the left side

7 x^{2} - 42 + 35 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 35 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 7 ( - 42 )}{2 \cdot 7}

3 5^{2} - 4 \cdot 7 (- 42) = 49

x_{1, 2} = \frac{- 35 \pm 49}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 35 + 49}{2 \cdot 7}, x_{2} = \frac{- 35 - 49}{2 \cdot 7}

x = \frac{- 35 + 49}{2 \cdot 7} : 1

x = \frac{- 35 - 49}{2 \cdot 7} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

- 2 x^{2} - 29 x - 14 = - 5 x

2 = y + 6 y^{2}

x^{2} + 20 x + 9 = 0

x^{2} + 9^{2} = 1 8^{2}

(3 x + 2)^{2} = 0

What are the solutions to the equation 7x^2-42=-35x ?
The solutions to the equation 7x^2-42=-35x are x=1,x=-6
Find the zeros of 7x^2-42=-35x
The zeros of 7x^2-42=-35x are x=1,x=-6