What are the solutions to the equation x^2+20x+9=0 ?

The solutions to the equation x^2+20x+9=0 are x=-10+sqrt(91),x=-10-sqrt(91)

Find the zeros of x^2+20x+9=0

The zeros of x^2+20x+9=0 are x=-10+sqrt(91),x=-10-sqrt(91)

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x^{2} + 20 x + 9 = 0

x = - 10 + 91, x = - 10 - 91

Decimal Notation

x = - 0.46060 \dots, x = - 19.53939 \dots

Solution steps

x^{2} + 20 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 9 = 291

x_{1, 2} = \frac{- 20 \pm 2 91}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 91}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 91}{2 \cdot 1}

x = \frac{- 20 + 2 91}{2 \cdot 1} : - 10 + 91

x = \frac{- 20 - 2 91}{2 \cdot 1} : - 10 - 91

The solutions to the quadratic equation are:

x = - 10 + 91, x = - 10 - 91

x^{2} + 9^{2} = 1 8^{2}

(3 x + 2)^{2} = 0

x^{2} + 25 = 16

x, 2 x^{2} + 5 y^{2} + 12 x - 20 y + 38 = 0

3 x^{2} + 23 x + 14 = 0

What are the solutions to the equation x^2+20x+9=0 ?
The solutions to the equation x^2+20x+9=0 are x=-10+sqrt(91),x=-10-sqrt(91)
Find the zeros of x^2+20x+9=0
The zeros of x^2+20x+9=0 are x=-10+sqrt(91),x=-10-sqrt(91)