What are the solutions to the equation -2x^2+9x+3=0 ?

The solutions to the equation -2x^2+9x+3=0 are x=-(-9+sqrt(105))/4 ,x=(9+sqrt(105))/4

Find the zeros of -2x^2+9x+3=0

The zeros of -2x^2+9x+3=0 are x=-(-9+sqrt(105))/4 ,x=(9+sqrt(105))/4

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- 2 x^{2} + 9 x + 3 = 0

x = - \frac{- 9 + 105}{4}, x = \frac{9 + 105}{4}

Decimal Notation

x = - 0.31173 \dots, x = 4.81173 \dots

Solution steps

- 2 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

9^{2} - 4 (- 2) \cdot 3 = 105

x_{1, 2} = \frac{- 9 \pm 105}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 9 + 105}{2 ( - 2 )}, x_{2} = \frac{- 9 - 105}{2 ( - 2 )}

x = \frac{- 9 + 105}{2 ( - 2 )} : - \frac{- 9 + 105}{4}

x = \frac{- 9 - 105}{2 ( - 2 )} : \frac{9 + 105}{4}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 105}{4}, x = \frac{9 + 105}{4}

2 x^{2} + 6 x + 7

x^{2} = 7 x

x^{2} + 12 = 6 x

2 y^{2} - 90 = 0

(2 x - 5) (3 x + 8) = 0

What are the solutions to the equation -2x^2+9x+3=0 ?
The solutions to the equation -2x^2+9x+3=0 are x=-(-9+sqrt(105))/4 ,x=(9+sqrt(105))/4
Find the zeros of -2x^2+9x+3=0
The zeros of -2x^2+9x+3=0 are x=-(-9+sqrt(105))/4 ,x=(9+sqrt(105))/4