What are the solutions to the equation -16x^2+176x+132=0 ?

The solutions to the equation -16x^2+176x+132=0 are x=-(-11+sqrt(154))/2 ,x=(11+sqrt(154))/2

Find the zeros of -16x^2+176x+132=0

The zeros of -16x^2+176x+132=0 are x=-(-11+sqrt(154))/2 ,x=(11+sqrt(154))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 x^{2} + 176 x + 132 = 0

x = - \frac{- 11 + 154}{2}, x = \frac{11 + 154}{2}

Decimal Notation

x = - 0.70483 \dots, x = 11.70483 \dots

Solution steps

- 16 x^{2} + 176 x + 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 176 \pm 17 6 ^{2} - 4 ( - 16 ) \cdot 132}{2 ( - 16 )}

17 6^{2} - 4 (- 16) \cdot 132 = 16154

x_{1, 2} = \frac{- 176 \pm 16 154}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 176 + 16 154}{2 ( - 16 )}, x_{2} = \frac{- 176 - 16 154}{2 ( - 16 )}

x = \frac{- 176 + 16 154}{2 ( - 16 )} : - \frac{- 11 + 154}{2}

x = \frac{- 176 - 16 154}{2 ( - 16 )} : \frac{11 + 154}{2}

The solutions to the quadratic equation are:

x = - \frac{- 11 + 154}{2}, x = \frac{11 + 154}{2}

- 16 t^{2} + 64 t + 60 = 120

5 x^{2} - 4 x + \frac{4}{5} = 0

a, (a - b)^{2} = 0

x^{2} + 5 = 7 x - 1

- 9 x^{2} + 8 x + 7 = 0

What are the solutions to the equation -16x^2+176x+132=0 ?
The solutions to the equation -16x^2+176x+132=0 are x=-(-11+sqrt(154))/2 ,x=(11+sqrt(154))/2
Find the zeros of -16x^2+176x+132=0
The zeros of -16x^2+176x+132=0 are x=-(-11+sqrt(154))/2 ,x=(11+sqrt(154))/2