What are the solutions to the equation 7x^2+56x-22=0 ?

The solutions to the equation 7x^2+56x-22=0 are x=(-28+sqrt(938))/7 ,x=-(28+sqrt(938))/7

Find the zeros of 7x^2+56x-22=0

The zeros of 7x^2+56x-22=0 are x=(-28+sqrt(938))/7 ,x=-(28+sqrt(938))/7

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7 x^{2} + 56 x - 22 = 0

x = \frac{- 28 + 938}{7}, x = - \frac{28 + 938}{7}

Decimal Notation

x = 0.37525 \dots, x = - 8.37525 \dots

Solution steps

7 x^{2} + 56 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 7 ( - 22 )}{2 \cdot 7}

5 6^{2} - 4 \cdot 7 (- 22) = 2938

x_{1, 2} = \frac{- 56 \pm 2 938}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 56 + 2 938}{2 \cdot 7}, x_{2} = \frac{- 56 - 2 938}{2 \cdot 7}

x = \frac{- 56 + 2 938}{2 \cdot 7} : \frac{- 28 + 938}{7}

x = \frac{- 56 - 2 938}{2 \cdot 7} : - \frac{28 + 938}{7}

The solutions to the quadratic equation are:

x = \frac{- 28 + 938}{7}, x = - \frac{28 + 938}{7}

x^{2} = 5

q^{2} = - 4

13870 = - 741 x^{2} + 1063 x + 13499

0 = 5 x^{2} - 35 x

2 a^{2} - 5 = 0

What are the solutions to the equation 7x^2+56x-22=0 ?
The solutions to the equation 7x^2+56x-22=0 are x=(-28+sqrt(938))/7 ,x=-(28+sqrt(938))/7
Find the zeros of 7x^2+56x-22=0
The zeros of 7x^2+56x-22=0 are x=(-28+sqrt(938))/7 ,x=-(28+sqrt(938))/7