What are the solutions to the equation -16t^2+40t=0 ?

The solutions to the equation -16t^2+40t=0 are t=0,t= 5/2

Find the zeros of -16t^2+40t=0

The zeros of -16t^2+40t=0 are t=0,t= 5/2

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- 16 t^{2} + 40 t = 0

t = 0, t = \frac{5}{2}

Decimal Notation

t = 0, t = 2.5

Solution steps

- 16 t^{2} + 40 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

4 0^{2} - 4 (- 16) \cdot 0 = 40

t_{1, 2} = \frac{- 40 \pm 40}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 40 + 40}{2 ( - 16 )}, t_{2} = \frac{- 40 - 40}{2 ( - 16 )}

t = \frac{- 40 + 40}{2 ( - 16 )} : 0

t = \frac{- 40 - 40}{2 ( - 16 )} : \frac{5}{2}

The solutions to the quadratic equation are:

t = 0, t = \frac{5}{2}

1 6^{2} + 25 y^{2} - 400 = 0

x, x^{2} y^{3} - 2 x y = 6 x + y + 1

y, x^{4} + 2 y^{2} = 6 x^{2} + 4 y - 5

2 x^{2} + 5 x + c = 0

5 x^{2} + 3 x

What are the solutions to the equation -16t^2+40t=0 ?
The solutions to the equation -16t^2+40t=0 are t=0,t= 5/2
Find the zeros of -16t^2+40t=0
The zeros of -16t^2+40t=0 are t=0,t= 5/2