What are the solutions to the equation 14x^2-336x-2592=0 ?

The solutions to the equation 14x^2-336x-2592=0 are x=(12(7+4sqrt(7)))/7 ,x=(12(7-4sqrt(7)))/7

Find the zeros of 14x^2-336x-2592=0

The zeros of 14x^2-336x-2592=0 are x=(12(7+4sqrt(7)))/7 ,x=(12(7-4sqrt(7)))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14 x^{2} - 336 x - 2592 = 0

x = \frac{12 ( 7 + 4 7 )}{7}, x = \frac{12 ( 7 - 4 7 )}{7}

Decimal Notation

x = 30.14229 \dots, x = - 6.14229 \dots

Solution steps

14 x^{2} - 336 x - 2592 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 336 ) \pm ( - 336 ) ^{2} - 4 \cdot 14 ( - 2592 )}{2 \cdot 14}

(- 336)^{2} - 4 \cdot 14 (- 2592) = 1927

x_{1, 2} = \frac{- ( - 336 ) \pm 192 7}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 336 ) + 192 7}{2 \cdot 14}, x_{2} = \frac{- ( - 336 ) - 192 7}{2 \cdot 14}

x = \frac{- ( - 336 ) + 192 7}{2 \cdot 14} : \frac{12 ( 7 + 4 7 )}{7}

x = \frac{- ( - 336 ) - 192 7}{2 \cdot 14} : \frac{12 ( 7 - 4 7 )}{7}

The solutions to the quadratic equation are:

x = \frac{12 ( 7 + 4 7 )}{7}, x = \frac{12 ( 7 - 4 7 )}{7}

(x - 9) (x - 7) = 0

24 x - 24 = 6 x^{2}

a^{2} + 2 a - 8 = 0

x^{2} + 9 x = 22

1 + 2 \frac{b}{3} + \frac{b ^{2}}{9} = 0

What are the solutions to the equation 14x^2-336x-2592=0 ?
The solutions to the equation 14x^2-336x-2592=0 are x=(12(7+4sqrt(7)))/7 ,x=(12(7-4sqrt(7)))/7
Find the zeros of 14x^2-336x-2592=0
The zeros of 14x^2-336x-2592=0 are x=(12(7+4sqrt(7)))/7 ,x=(12(7-4sqrt(7)))/7