What are the solutions to the equation 1+2 b/3+(b^2)/9 =0 ?

The solutions to the equation 1+2 b/3+(b^2)/9 =0 are b=-3

Find the zeros of 1+2 b/3+(b^2)/9 =0

The zeros of 1+2 b/3+(b^2)/9 =0 are b=-3

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1 + 2 \frac{b}{3} + \frac{b ^{2}}{9} = 0

b = - 3

Solution steps

1 + 2 \cdot \frac{b}{3} + \frac{b ^{2}}{9} = 0

Multiply both sides by

9

b^{2} + 6 b + 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

b_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

b = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

b = - 3

The solution to the quadratic equation is:

b = - 3

(3 x - 2) (x + 6) = 0

x^{2} = \frac{8}{3} x - \frac{3}{4}

4 x^{2} + 12 x - 40 = 0

X^{2} - 11 X + 24 = 0

\frac{x ^{2}}{3} = 48

What are the solutions to the equation 1+2 b/3+(b^2)/9 =0 ?
The solutions to the equation 1+2 b/3+(b^2)/9 =0 are b=-3
Find the zeros of 1+2 b/3+(b^2)/9 =0
The zeros of 1+2 b/3+(b^2)/9 =0 are b=-3