What are the solutions to the equation (3x-2)(x+6)=0 ?

The solutions to the equation (3x-2)(x+6)=0 are x= 2/3 ,x=-6

Find the zeros of (3x-2)(x+6)=0

The zeros of (3x-2)(x+6)=0 are x= 2/3 ,x=-6

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(3 x - 2) (x + 6) = 0

x = \frac{2}{3}, x = - 6

Decimal Notation

x = 0.66666 \dots, x = - 6

Solution steps

(3 x - 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x + 6 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 6

x^{2} = \frac{8}{3} x - \frac{3}{4}

4 x^{2} + 12 x - 40 = 0

X^{2} - 11 X + 24 = 0

\frac{x ^{2}}{3} = 48

- y^{2} + 21 y - 104 = 0

What are the solutions to the equation (3x-2)(x+6)=0 ?
The solutions to the equation (3x-2)(x+6)=0 are x= 2/3 ,x=-6
Find the zeros of (3x-2)(x+6)=0
The zeros of (3x-2)(x+6)=0 are x= 2/3 ,x=-6